Which value is in the domain of g(x) = sqrt(x - 2)?

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Study for the Praxis 5165 Mathematics Test. Review with flashcards and multiple-choice questions, each with hints and explanations. Prepare effectively for success!

Multiple Choice

Which value is in the domain of g(x) = sqrt(x - 2)?

Explanation:
For the square root to be defined with real numbers, the radicand must be nonnegative. So for g(x) = sqrt(x - 2), we need x - 2 >= 0, which means x >= 2. Among the given values, only 2 satisfies this condition (since sqrt(0) = 0 is allowed). The others—1, 0, and -1—make x - 2 negative, which would not be a real value under the square root. Therefore, the value in the domain is 2.

For the square root to be defined with real numbers, the radicand must be nonnegative. So for g(x) = sqrt(x - 2), we need x - 2 >= 0, which means x >= 2. Among the given values, only 2 satisfies this condition (since sqrt(0) = 0 is allowed). The others—1, 0, and -1—make x - 2 negative, which would not be a real value under the square root. Therefore, the value in the domain is 2.

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